I need a method (or an addition to cy.intercept() ) to be able to ignore waiting for a load for a get. It every time delays the time it takes to execute the test and eats up a lot of time for nothing.

How can I complete or modify cy.intercept('api.link.url' ,null).as('url') so I can exclude it from the load and have the test ignore it? (with null it doesn't work)

I hope I have conveyed all the information correctly. Thank you!

CodePudding user response：

Assuming your website doesn't need the request to complete to actually run the application, and there will be no impact from not returning a real-like response, you can simply return a 200.

cy.intercept('/foo', {statusCode: 200}).as('url')

If you do need a response body, I'd suggest saving that response into a file in your fixtures/ folder, and returning that response.

cy.intercept('/foo', {statusCode: 200, fixture: 'bar'}).as('url')

CodePudding user response：

Use an empty object instead of null

cy.intercept('api.link.url' , {})