Python Selenium navigate and click a menu voice-CodePudding

i have a website made of a table. Each row has two a link elements. Clicking on the second one it triggers a javascript which opens a menu.

With selenium i should navigate that menu till the "Properties" voice and to its relative submenu voice "Versions".

i tried with a simple find_element by Link_text, but it won't find the item

driver.find_element(by=By.LINK_TEXT, value="Properties").click()

i also tried with a try block but still won't find my element

try:
    myElem = WebDriverWait(driver, delay).until(EC.presence_of_element_located((By.LINK_TEXT, "Properties")))
    print("Found")
except TimeoutException:
    print("Not Found!")

how can i access that element? I need to select the menu voice "Properties", this way will be showed a submenu with the voice "Versions" which is the one i need to click.

How to do that?

here i attach a sample of the html code of the page

<td  scope="rowgroup" nowrap="" width="100%">
    <a  href="/test/">test link</a>
    <a href="" onclick="showFunctionMenu2('rand', 7978424, event, '', '' );setSectionName('');return false"></a>
    <div  style="left: 359px; top: 516px; z-index: 5; visibility: visible;">
        <span >
            <div
                
                onclick="javascript:popup_callback( escape( '/testlink/test12' ),'');return false;"
                onm ouseover="javascript:hiLight( 'mymenu0' );doSubMenu( 'mymenu0', 'funMenu4124' );"
                onm ouseout="javascript:loLight( 'mymenu0' );"
                width="100%"
            >
                <a href="javascript:popup_callback( escape( '/testlink/test12' ),'');" onfocus="doSubMenu( 'mymenu0', 'funMenu4124' );">Download</a>
            </div>
            <div id="mymenu14"  onm ouseover="javascript:hiLight( 'mymenu14' );doSubMenu( 'mymenu14', 'funMenu4124' );" width="100%">
                <div  onclick="javascript:doKeyboardSubMenu( 'mymenu14', 'funMenu4124', event );return false;">
                    <a href="javascript:doSubMenu( 'mymenu14', 'funMenu4124' );">Properties</a>
                </div>
            </div>
            <div ><img src="/tessst/spacer.gif" alt="" width="1" height="1" /></div>
        </span>
        <span  id="mymenu14Sub">
            <div
                
                onclick="javascript:popup_callback( escape( '/testlink/viewType=1' ), '' );return false;"
                onm ouseover="javascript:hiLight( 'mymenu14.0' );doSubMenu( 'mymenu14.0', 'mymenu14Sub' );"
                onm ouseout="javascript:loLight( 'mymenu14.0' );"
                width="100%"
            >
                <a href="/testlink/viewType=1">General</a>
            </div>
            <div
                
                onclick="javascript:popup_callback( escape( '/testlink/3D1' ), '' );return false;"
                onm ouseover="javascript:hiLight( 'mymenu14.5' );doSubMenu( 'mymenu14.5', 'mymenu14Sub' );"
                onm ouseout="javascript:loLight( 'mymenu14.5' );"
                width="100%"
            >
                <a href="/testlink/func=ll&amp;objId=79">Versions</a>
            </div>
            <div ><img src="/tessst/spacer.gif" alt="" width="1" height="1" /></div>
        </span>
    </div>
</td>

CodePudding user response：

Try doing the following:

driver.find_element(By.XPATH, f"{xpath}")

In this case xpath would be the link's xpath. If your wondering how to get xpath then go right-click inspect the link element. Then the elements "source code" will come up on the right. Right-click that and click copy > copy full xpath.

CodePudding user response：

Actually, You are on the right direction but the problem is that the webdriver can't render the complex JavaScript here. So in that case, it is badly in need execute_script to render it.

myElem = WebDriverWait(driver, delay).until(EC.presence_of_element_located((By.LINK_TEXT, "Properties")))
driver.execute_script("arguments[0].click();", myElem )