Rename part of the directory names?-CodePudding

The following command found the following directories.

$ find tmp/ -name "date=*" -type d
tmp/year=2022/month=05/date=27
tmp/year=2022/month=05/date=21
tmp/year=2022/month=05/date=29
tmp/year=2022/month=05/date=24
tmp/year=2022/month=05/date=31
tmp/year=2022/month=06/date=01
tmp/year=2022/month=06/date=02

I need to rename the directories by replacing date= to day=.

find tmp/ -name "date=*" -type d -exec rename s/date=/day=/g "{}"  ;

However, the command doesn't rename the directories?

I will need to implement it in Python.

CodePudding user response：

rename utility is not part of standard Unix tool/utilities and comes in different flavors.

I may suggest sticking with bash and mv using this find command:

find tmp -name "date=*" -type d -exec bash -c '
   for f;do echo mv "$f" "${f/date=/day=}"; done' _ {}

I have kept echo before mv for your testing purpose. Once satisfied with the output just remove echo from above command.

CodePudding user response：

If you want to do this from Python anyway, a subprocess is just unnecessary.

import os

for curdir, dirs, files in os.walk("/tmp"):
    for dirname in dirs:
        if dirname.startswith("date="):
            new = dirname.replace("date=", "day=")
            os.rename(os.path.join(curdir, dirname), os.path.join(curdir, new))

CodePudding user response：

If you are on Python 3.4 , you can use pathlib:

from pathlib import Path

tmp = Path('tmp')

for o in tmp.rglob('date=*'):
    if o.is_dir():
        o.rename(o.parent / o.name.replace('date', 'day'))