Print binary reprensentation of individual characters-CodePudding

I have a function that converts characters to binary

def binary(value):
    return ''.join(format(ord(i), 'b') for i in value)

print(binary('a'))  # 1100001  
print(binary('b'))  # 1100010

But when I give multiple characters, they are joined together

print(binary('ab')) # 11000011100010

I want to find a way to split these apart into the individual letters. E.g.

'11000011100010' -> '1100001 1100010'

CodePudding user response：

The best way is to store all the generated binaries in a list then join all the items.

output=[]
def binary(a):
    binary = ''.join(format(ord(i), '08b') for i in a)
    #print(binary)
    output.append(binary)

def split_string(a):
    for i in a:
        binary(i)
   
split_string('ram')
print("output: ", ' '.join(map(str,output)))

you will get the output like below.

output:  01110010 01100001 01101101

CodePudding user response：

You lose any spacing information with ''.join. Instead, format each character, then join later.

def binary(value):
    for c in value:
         yield format(ord(c), 'b')


print(' '.join([x for x in binary('ab')]))
# '1100001 1100010'

CodePudding user response：

Your binary sequences have a length that's the number of bits required to just represent the number (happens to be 7 in both cases here) - but they could be very different lengths. You are throwing that information away in your ''.join() call and there's no way to retrieve that. Why not return a list of strings, instead of concatenating them all?

I.e:

# when passed value='ab', this will compute the binary representation of 'a'
# and then 'b', both 7 bits, and combine them into a single string of bits,
# 14 characters long; however the fact that these strings were both 7 
# characters long gets lost (could have been 6 8, 8 6, etc.)
def binary(value):
    return ''.join(format(ord(i), 'b') for i in value)


print(binary('ab'))  # prints all 14 characters

So, if you instead:

def binary(value):
    return [format(ord(i), 'b') for i in value]


print(binary('ab'))

The result is:

['1100001', '1100010']

You can work with those like this:

bs = binary('ab')
print(bs[0])
print(bs[1])
print(''.join(bs))

Result:

1100001
1100010
11000011100010

If, for example, you just want a space between each block:

print(' '.join(bs))

Result:

1100001 1100010

Padding to 8-bit words:

print(' '.join(b.zfill(8) for b in bs))

Result:

01100001 01100010

However, be careful with something like bs = binary('课题').