How to access parent text which has no tag through xPath-CodePudding

Please find the code below

<div >
                        <label  rel="tooltip" title="Proprietary/trade name of the medical device as used in the labeling or catalog.">Brand Name:</label>
                        Snowden-Pencer
                        <br>
                        <label  rel="tooltip" title="Identifies a category or design of devices that have specifications, performance, size, and composition within limits set by the company.">Version or Model:</label>
                        32-0044
                        <br>
                        <label  href="#" rel="tooltip" title="Whether the device is currently offered for sale by the device company. A device no longer in commercial distribution may or may not still be available for purchase in the marketplace.">Commercial Distribution Status:</label>
                        In Commercial Distribution
                        <br>
                        <label >Catalog Number:</label>
                        32-0044
                        <br>
                        <label >Company Name:</label>
                        CAREFUSION 2200, INC
                    </div>

I have to retrieve parent text like "Snowden-Pencer", "32-0044","CAREFUSION 2200, INC" individually

This is what I have tried

element = WebDriverWait(driver, 10).until(
        EC.presence_of_element_located((By.XPATH, "/html/body/div[1]/div[1]/div[2]/div[1]/div[2]/section[1]/div[1]/div[1]//div[1]/*"))
    )

Output is:

output = Brand Name:

I need to find the correct XPath. Please help me out, thanks in advance

CodePudding user response：

If you're using selenium you can use the getText() method so it will perhaps look like driver.findElement(webdriver.By.xpath("XPath")).getText() Altought that's for Java.

For python I believe it looks something like this

value_text = driver.find_element_by_xpath("XPath").text

CodePudding user response：

Can you try below two xpaths

//label[@rel='toltip']/*

CodePudding user response：

you can use regex

import re
a = """<div >
                        <label  rel="tooltip" title="Proprietary/trade name of the medical device as used in the labeling or catalog.">Brand Name:</label>
                        Snowden-Pencer
                        <br>
                        <label  rel="tooltip" title="Identifies a category or design of devices that have specifications, performance, size, and composition within limits set by the company.">Version or Model:</label>
                        32-0044
                        <br>
                        <label  href="#" rel="tooltip" title="Whether the device is currently offered for sale by the device company. A device no longer in commercial distribution may or may not still be available for purchase in the marketplace.">Commercial Distribution Status:</label>
                        In Commercial Distribution
                        <br>
                        <label >Catalog Number:</label>
                        32-0044
                        <br>
                        <label >Company Name:</label>
                        CAREFUSION 2200, INC
                    </div>"""
b = re.findall(r' (.*?)\n', a)
c = [x.lstrip().rstrip() for x in b if '<' not in x and '>' not in x]