Convert list to dictionary using same default key-CodePudding

I have a list which looks like this:

lst = ['a', 'b', 'c']

I want to iterate through that list to get a dictionary like:

dict = {'jobs': [{'id':'a'}], [{'id':'b'}], [{'id':'c'}]}

I tried looping through the elements of the list, like:

lst = ['a', 'b', 'c']
dict = {'jobs':[{}]}
for key in range(len(lst)):
    dict['jobs'][key]['id'] = list[key]

print(dict)

But I get an out of range error.

Any suggestions?

CodePudding user response：

You can use:

lst = ['a', 'b', 'c']
{'jobs' : [{'id' : x} for x in lst]}

# {'jobs': [{'id': 'a'}, {'id': 'b'}, {'id': 'c'}]}