JavaScript Sort by number in a string-CodePudding

How could i sort e.g an array like this one:

[
  '<@520968882077433856> is level **7,64** _(18115.5 total xp)_',
  '<@289037609274048513> is level **7,07** _(14473 total xp)_',
  '<@672835870080106509> is level **8,25** _(22473.5 total xp)_',
  '<@536686935134175254> is level **6,22** _(10184.5 total xp)_',
]

I would like to sort it by the amount of total xp, so the number within the brackets.

CodePudding user response：

You can use the sort callback. Extract the number with a regular expression:

const data = [
  '<@520968882077433856> is level **7,64** _(18115.5 total xp)_',
  '<@289037609274048513> is level **7,07** _(14473 total xp)_',
  '<@672835870080106509> is level **8,25** _(22473.5 total xp)_',
  '<@536686935134175254> is level **6,22** _(10184.5 total xp)_',
];

const regex = /(?<=_\()[\d.] /;
data.sort((a, b) =>  a.match(regex) -  b.match(regex));
console.log(data);

The is used to convert the returned array (with one match element) to a string and then that to a number. You could use ?.[0] to actually get that first array element.

CodePudding user response：

Here is another try, looking for a space after the number:

const arr=[
  '<@520968882077433856> is level **7,64** _(18115.5 total xp)_',
  '<@289037609274048513> is level **7,07** _(14473 total xp)_',
  '<@672835870080106509> is level **8,25** _(22473.5 total xp)_',
  '<@536686935134175254> is level **6,22** _(10184.5 total xp)_',
];

function getN(s){
 return s.match(/_\((. ?) /)[1];
}
arr.sort((a,b)=>getN(a)-getN(b))

console.log(arr)

CodePudding user response：

We can try sorting using a custom lambda expression:

var input = [
    '<@520968882077433856> is level **7,64** _(18115.5 total xp)_',
    '<@289037609274048513> is level **7,07** _(14473 total xp)_',
    '<@672835870080106509> is level **8,25** _(22473.5 total xp)_',
    '<@536686935134175254> is level **6,22** _(10184.5 total xp)_',
];
var output = input.sort( (a, b) => parseFloat(a.match(/(\d (?:\.\d )?) total xp\b/)[1]) - parseFloat(b.match(/(\d (?:\.\d )?) total xp\b/)[1]));
console.log(output);

In the above we are extracting the number which is followed by total xp, parsing it as a float, and then using that value in the sorting comparator. If you want descending order, then just reverse the inequality in the lambda function.

CodePudding user response：

Please try this.

const array = [
    "<@520968882077433856> is level **7,64** _(18115.5 total xp)_",
    "<@289037609274048513> is level **7,07** _(14473 total xp)_",
    "<@672835870080106509> is level **8,25** _(22473.5 total xp)_",
    "<@536686935134175254> is level **6,22** _(10184.5 total xp)_",
];

const extractDigitNumber = (string) => {
    return string.match(/(?<=\_\()(.*?)(?=\)\_)/)[0].replace(/[^\d\.] /g, '') 
}

array.sort((a, b) => {
    return extractDigitNumber(a) - extractDigitNumber(b)
})

console.log(array)

CodePudding user response：

Details are commented in example

let data = [
  '<@520968882077433856> is level **7,64** _(18115.5 total xp)_',
  '<@289037609274048513> is level **7,07** _(14473 total xp)_',
  '<@672835870080106509> is level **8,25** _(22473.5 total xp)_',
  '<@536686935134175254> is level **6,22** _(10184.5 total xp)_',
]

/*
* - .map() through array 
* - on every iteration run .match() using this regex:
*   /(\d \.?\d*)(?=\stotal)/ which means:
    "match one or more numbers, then a possible dot,
    and then possible numbers, but only if it's followed
    by a space and literal 'total'"
* - return a match in an array and the current index
* - .sort() the sub-arrays by their first index (sub[0])
*/
let indices = data.map((str, idx) => [ str.match(/(\d \.?\d*)(?=\stotal)/g), idx]).sort((a, b) => a[0] - b[0]);
console.log(JSON.stringify(indices));

//Define an empty array
let result = [];
/*
* - run new array of arrays with .forEach()
* - get the string within the original array (data) by
    the current sub-array's second index (sub[1])
* - push the value into the empty array (result)
*/
indices.forEach((sub, idx) => result.push(data[sub[1]]));
console.log(result);