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How do I use the new launchUrl() method with a "mailto:" link?

Time:07-02

I have a little link in my app that says "Send us an e-mail". When you click it, I want the default email app to open, with an email started to our email address. I used to make it do exactly that with the launch() method in the url_launcher package like this:

import 'package:url_launcher/url_launcher.dart' as url;

Future<bool?> pressedSendUsEmail() async {
  bool? success;
  try {
    print('Pressed Send us an e-mail...');
    success = await url.launch('mailto:[email protected]');  // Works like a charm...
    print('success is $success');
  } catch (e) {
    print('Caught an error in Send us an e-mail!');
    print('e is: ${e.toString()}');
  }
  return success;
}

But now, I get a warning saying launch() is deprecated! I should use launchUrl() instead. But launchUrl() doesn't take a String argument, it takes a Uri argument... and I don't know how to write this Uri correctly, so that it does what I want! I tried:

  success = await url.launchUrl(Uri(path: 'mailto:[email protected]'));

but that throws an error, because it can't interpret the ":" character. I've tried:

  success = await url.launchUrl(
    Uri.https('mailto:[email protected]', ''),
  );

and that launches the link, but in the browser... and it doesn't start up an e-mail to the pre-printed address. I tried adding:

  success = await url.launchUrl(
    Uri.https('mailto:[email protected]', ''),
    mode: url.LaunchMode.externalApplication,
  );

and that gives me an option of which external app to open the link with, but unfortunately, only browser apps are listed... not the email app!

How should I write my command to make the launchUrl() just do exactly what the old launch() did?? Most grateful for help!

CodePudding user response:

Try this:

void _sendEmail(){
  String? encodeQueryParameters(Map<String, String> params) {
    return params.entries.map((e) =>   
    '${Uri.encodeComponent(e.key)}=${Uri.encodeComponent(e.value)}')
      .join('&');
  }

  final Uri emailLaunchUri = Uri(
    scheme: 'mailto',
    path: '[email protected]',
    query: encodeQueryParameters(<String, String>{
       'subject': 'CallOut user Profile',
       'body': widget.userModel?.username ?? ''
      }),
    );
    launchUrl(emailLaunchUri);
}

CodePudding user response:

No need for the other answer's pointless redundant subroutine when it's already built in to Uri!

void _sendEmail(){

  final Uri emailLaunchUri = Uri(
    scheme: 'mailto',
    path: '[email protected]',
    queryParameters: {
       'subject': 'CallOut user Profile',
       'body': widget.userModel?.username ?? ''
      }),
    );
launchUrl(emailLaunchUri);

}

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