$vacancies = 13;
    $list_order_id = [ 1, 5, 6, 9, 10 ];

    $arrayOrder = [];

    $last_id = 6;

    for ( $i = 0; $i < $vacancies; $i   )
    {
        // last_id = 6
        // next id = 9 ( starter )
        // result => $arrayOrder = [ 9, 10, 1, 5, 6, 9, 10, 1, 5, 6, 9, 10, 1 ];
        anyone help me find this result?
    }

I need make array result from the initial value by number of vacancies

thanks

CodePudding user response：

$vacancies = 13;
$list_order_id = [ 1, 5, 6, 9, 10 ];
$last_id = 6;

// Count of ids
$count = count($list_order_id);

// How many times does the list of ids need to be repeated so that there are enough items
$times = intdiv($vacancies, $count)   2;

// Repeat the list of ids that many times
$list = array_merge(... array_fill(0, $times, $list_order_id));

// Index of the first occurrence of the element the list should start with
$start = array_search($last_id, $list)   1;

// Extract the slice starting at that index with the desired length
$result = array_slice($list, $start, $vacancies);

print_r($result);

Output:

Array
(
    [0] => 9
    [1] => 10
    [2] => 1
    [3] => 5
    [4] => 6
    [5] => 9
    [6] => 10
    [7] => 1
    [8] => 5
    [9] => 6
    [10] => 9
    [11] => 10
    [12] => 1
)

CodePudding user response：

You have supplied the lookup array, the number of iterations, and the value before the starting value.

The only things left to do are:

1. Find the count of the lookup,
2. Find the index of the last value in the lookup,
3. Loop the expressed number of times,
4. Use a modulus calculation to find the next appropriate value in the lookup, and
5. Push values into the result array.

This can be done with no iterated function calls.

Code: (Demo)

$count = count($list_order_id);
$index = array_search($last_id, $list_order_id);
$result = [];
for ($i = 0; $i < $vacancies;   $i) {
    $result[] = $list_order_id[  $index % $count];
}
var_export($result);