Work around to access variable and functions within jQuery .ready() function?-CodePudding

Hi guys I need to test if a jquery script like the below one contains a given function (for example foo):

$( document ).ready( function() {
  let n = 5;
  function foo() {
    console.log(n * 2)
  }

  foo();
})

I tried this function to test whether is function or not:

function isFunction(x) {return Object.prototype.toString.call(x) === '[object Function]'}

but it didn't because of the closure and eventually, I end up with a function not defined error.

CodePudding user response：

What about something like this. Granted this is pretty outside-the-box thinking and will become broken if you change the name of the foo() function ever.

function readyCallback(){
  let n = 5;
  function foo() {
    console.log(n * 2)
  }

  foo();
}
$( document ).ready(readyCallback);

const testBoolean = readyCallback.toString().includes('function foo()');

console.log(testBoolean ? "The Test Has Passed" : 'The Test Has Failed')

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>