how to make random value in range a-z with python-CodePudding

i have python code which it will generate random value like

JAY5uFy4F

this is the first output when i run python script this is my code:

a= []
n=1
c=1
c2=3
Start= 10**(n-1)
End= (10**n)-1
while 1 :
    Num= random.randint(Start,End)
    Text= string.ascii_letters
    txt=''.join(random.choice(Text) for i in range(c))
    txt2=''.join(random.choice(Text) for i in range(c2))

    def Value():
        V= random.randint(3,6)
        vl= (f"JAY{V}{txt2}{Num}{txt}")
        return (vl)
    passwd =Value()
    if (passwd) not in (a):
        a.append (passwd)
        print(a)
    else:
        break

I know the code above will generate the sentence "JAY..." randomly but what I want is to get [az][AZ] after the word "JAY..."

for example:

JAY5abc1d JAY5bcd1e JAY5cde1f

etc and also uppercase characters

JAY5Abc1d JAY5Bcd1e JAY5Cde1f

until z, then when it reaches the last character the number changes

JAY5Abc2d JAY5Bcd2e JAY5Cde2f

can anyone help me please

CodePudding user response：

I'd use itertools.product to iterate deterministically, rather than using a randomized algorithm.

Something like would seem to do what you want:

import itertools
from string import ascii_letters

def make_options(n, c1, c2):
  parts = [
    ['JAY'],
    map(str, range(3, 7)),
    *([ascii_letters] * c1),
    map(str, range(10**(n-1), 10**n)),
    *([ascii_letters] * c2),
  ]
  for cs in itertools.product(*parts):
    yield ''.join(cs)

I'm using an iterator because this will be a long list, and trying to keep the whole thing in memory at once will probably fail.

If you keep your parameters in the small part of the space, you can easily get an array out of this by doing:

a = list(make_options(1, 1, 1))

but note that this is already 97k entries.