How do I access the "yes" and "no" keys in my dictionary and put their values in-CodePudding

from pathlib import Path
from collections import Counter

counter = Counter()
dir = Path(r'C:\Users\user\OneDrive\somedirectory\pvi_textgrid')
out_file = Path('output.txt')

for file in dir.glob('*.textgrid'):
    with file.open('r', encoding='utf-8') as f:
        for l in f:
            counter.update(l.strip().split())

counter.most_common(1)

with out_file.open('w', encoding='utf-8') as f:
    f.write(",".join(counter))
print(counter)

output is as such

Counter({'0': 133,
         '""': 73,
         '"IntervalTier"': 57,
         '=': 38,
         '1': 38,
         '3': 35,
         'File': 19,
         'type': 19,
         '"ooTextFile"': 19,
         'Object': 19,
         'class': 19,
         '"TextGrid"': 19,
         '<exists>': 19,
         '"Phonation"': 19,
         '"Speech"': 19,
         '"Comments"': 19,
         '3.93': 14,
         '3.96': 7,
         '5.0200000000000005': 7,
         '3.77': 7,
         '10.21': 7,
         '12.52': 7,
         '11.370000000000001': 7,
         '3.7800000000000002': 7,
         '3.72': 7,
         '12.1': 7,
         '3.97': 7,
         '3.89': 7,
         '5.94': 7,
         '6.2': 7,
         '4.63': 7,
         '4.18': 7,
         '4.62': 7,
         '6.83': 7,
         '"no"': 4,
         '2': 3,
         '0.36100874171044706': 2,
         '1.0890132576679536': 2,
         '0.7216091094277167': 2,
         '1.3713701493710988': 2,
         '0.7099782814647281': 2,
         '1.4161172126881183': 2,
         '0.8348417168127676': 2,
         '3.2335119433221124': 2,
         'five"': 2,
         '1.7299889316602575': 2,
         '2.480568841515854': 2,
         '2.148692441200811': 2,
         '"aa"': 2,
         '2.1688157906233343': 2,
         '1.2904978880596738': 2,
         '0.5533687507723187': 2,
         '0.9558305467454027': 2,
         '0.4383214942352268': 2,
         '0.9760798418291502': 2,
         '0.985814582373786': 2,
         '10.873283112340998': 2,
         '0.7770649427891344': 2,
         '1.1413355432567072': 2,
         '0.5661048087832754': 2,
         '1.0812964186884253': 2,
         '0.7924526404870945': 2,
         '3.11139917918915': 2,
         '0.5212286824463059': 2,
         '3.472996059458859': 2,
         '1.5274624044665293': 2,
         '1.9402683705731323': 2,
         '"yes"': 2,
         '0.991847317448846': 2,
         '1.7480710757789653': 2,
         '0.9602805622853893': 2,
         '2.863884865551033': 2,
         '0.9643968456947999': 2,
         '3.140083120204604': 2,
         '"cancel"': 1,
         '"help"': 1,
         '"quit"': 1,
         '"three': 1,
         'six': 1,
         '"thirty': 1,
         '"ee"': 1,
         '"oo"': 1,
         '"you': 1,
         'wish': 1,
         'to': 1,
         'know': 1,
         'all': 1,
         'about': 1,
         'my': 1,
         'grandfather"': 1,
         '"well': 1,
         'he': 1,
         'is': 1,
         'nearly': 1,
         'ninety': 1,
         'three': 1,
         'years': 1,
         'old"': 1,
         '"eleven': 1,
         'thousand': 1,
         'one"': 1,
         '"oh': 1,
         'zero': 1,
         'ten"': 1})

I want to access the "yes" and "no" keys and put their values in to another variable to show the amount of times they are mentioned

CodePudding user response：

You can access the count of words via counter :

yes_counts = counter['yes']
no_counts = counter['no']