How to replace list items in order of another list in Python-CodePudding

Let's take this list:

list2 = ['<@25032923629058>', 'dad', 'awd', '<@65432156029058>', '<@98450239029058>']

I would like to replace the elements that start with <@ in order of this list:

list = ['dd#1111', 'dd#2222', 'dd#333']

Expected result:

['dd#1111', 'dad', 'awd', 'dd#2222', 'dd#333']

The following script changes every item that starts with <@ with the same value, which i want to avoid:

for i in range(len(list2)):
    if list2[i].startswith("<@"):
        list2[i] = list[0]
print(list2)

CodePudding user response：

A simple fix, delete list[0] after replacing it.

for i in range(len(list2)):
    if list2[i].startswith("<@"):
        list2[i] = list[0]
        del list[0]
print(list2)

On a second note, don't name your lists as list. This is a bad practice that will hurt you in the long run.

CodePudding user response：

you could use counter to in order to replace your words in list2 with different words from list each time

I would also suggest not using the name list for your list since it has spacial meaning in python

This should do the trick :

list2 = ['<@25032923629058>', 'dad', 'awd', '<@65432156029058>', '<@98450239029058>']
list = ['dd#1111', 'dd#2222', 'dd#333']
count=0
for i in range(len(list2)):
    if list2[i].startswith("<@"):
        list2[i] = list[count]
        count =1
print(list2)

output:

['dd#1111', 'dad', 'awd', 'dd#2222', 'dd#333']