in python when using "range" in for loop for the list (n) , it shows wrong output but with-CodePudding

1) with "range" in for loop (with wrong output)

n=[3,5,1,0,2]
even_count, odd_count = 0,0

for i in range(0,len(n)):
    if (i%2==0):
        even_count =1 
    else:
        odd_count =1

print("total even nos. are:",even_count)
print("total odd nos. are:",odd_count)

Output:

total even nos. are: 3
total odd nos. are: 2

2) Without "range" in for loop (with correct output):

n=[3,5,1,0,2]
even_count, odd_count = 0,0

for i in (n):
    if (i%2==0):
        even_count =1 
    else:
        odd_count =1
        
print("total even nos. are:",even_count) 
print("total odd nos. are:",odd_count)

Output:

total even nos. are: 2
total odd nos. are: 3

CodePudding user response：

If using range, i is the index. You can test this by using:

>>> for i in range(5):
...     print(i)
0
1
2
3
4

To check if the number is even, use if num[i] % 2 == 0:

Just as a sidenote, your code can be simplified further:

>>> even_count = len([x for x in n if not x % 2])
>>> odd_count = len([x for x in n if x % 2])
>>> even_count, odd_count
(2, 3)

CodePudding user response：

when you use for i in n you re iterating over the list so i gonna take the list values in this case i=3 then on the second loop i=5 ....