How To Make a program for grade of students without if else statements in python-CodePudding

Actually, I am a beginner. So Help Me Accordingly. I am Confused, How We Will Be Able To Generate The Same Output Without using if_else, By Using Basics.

#We Really Stalk Code!! :)
M = int(input("Enter The Marks Of Maths(Out OF 100) "))
S = int(input("Enter The Marks Of Science(Out OF 100) "))
E = int(input("Enter The Marks Of English(Out OF 100) "))
TOT=M S E
print("Total Marks",TOT,sep=" ")
PER= (M S E)/3
print("Percentage",round(PER,2),sep=" ")
#Now I want The Below Code To Be Run Without The Use Of if_else
if(PER>50):
  print("A")
elif(PER>0):
 print("B")

elif(PER==0):
  print("C")

CodePudding user response：

If else is the basics. There's literally no more basic construct in programming. Any alternative mechanism of accomplishing this is going to use a more complicated construct (a data structure, a goto or a loop)

Python does have alternative control flow statements. It has goto, and if can be implemented using while and break as follows

while per > 50:
   print("A")
   break

But if-else is always the correct way to do this in Python.

Artificial restrictions don't teach you to be a good programmer. You don't learn to become a good writer by writing an entire essay without using the letter e. You don't learn to become a good footba player by not using your feet. You don't become a better cook by cutting all your vegetables with a spoon.

CodePudding user response：

An alternative to if else in python is switch case in python. Implementing switch case in python can be acheived with the help of dictionary in python.

CodePudding user response：

@NickBailey 's answer is the simplest and probably the best route without if-else statements.

You can also use boolean logic to figure out if the grade should be an A, B, or C with a dictionary.


# Figure out if it's an A, B, or C (only one can be True)
is_a = PER > 50
is_b = PER <= 50 and PER > 0
is_c = PER == 0

# Assign key,val pairs to each grade
grade_values = {
    is_a: "A",
    is_b: "B",
    is_c: "C",
}

# Since only one grade can evaluate to True, grade_values[True] will return the correct grade
grade = grade_values[True]

print(grade)