I have a slice of integers which I need to cut into smaller slices and use these new slices to a function call. I have to put 5 objects into every new slice. I could implement a solution which works correctly if the length of the arr1 is dividable with 5. However in other cases I will get an out of range error like this: panic: runtime error: slice bounds out of range [:26] with capacity 24. I understand the problem and its cause, I give wrong index values at the last loop, my logic fails when arr1_len can't be divided by 5. My question is that how could I slice arr1 into new slices with 5 objects in every slice, except the last one which can hold less than 5.? Playground link

package main

import "fmt"

func printRes(l []int) {
    fmt.Println(l)
}

func sliceTest() {
    arr1 := []int{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23}
    arr1_len := len(arr1)
    val := 5
    val2 := 0
    for i := 0; i <= arr1_len; i = i   val {
        val2 = i   val
        currentSlice := arr1[i:val2]
        fmt.Println(i, val2, currentSlice)
        printRes(currentSlice)
    }
}

func main() {
    sliceTest()
}

CodePudding user response：

Check bounds:

val2 = i   val
if val2 >= len(arr1) {
    val2 = len(arr1)
}