How to delete the extra sections of IP on Scarpy?-CodePudding

When you run the following code on Google:

response.ip_address

Her values equal to:

IPv4Address('79.127.127.87')

Screenshot:

But the expected answer is as follows:

'79.127.127.87'

How to get this answer?

CodePudding user response：

Just use str():

scrapy shell

In [1]: url='https://httpbin.org/'

In [2]: req = scrapy.Request(url=url)

In [3]: fetch(req)
[scrapy.core.engine] INFO: Spider opened
[scrapy.core.engine] DEBUG: Crawled (200) <GET https://httpbin.org/> (referer: None)

In [4]: str(response.ip_address)
Out[4]: '3.93.133.228'

CodePudding user response：

As you not mentioned complete code , I'm suggesting this method...Have you tried post processing?

import re
ip = """(IPv4Address('79.127.127.87')"""

out = re.findall(r"'(.*?)'", ip, re.DOTALL)
#print(out)
#print(type(out))

ip_final = s = ''.join(out)
print(ip_final)

output

79.127.127.87