I am having one line I have to replace that below is the line

/myhome/ishere/where/are.you.ha

Here I have a live regex

preg_match('/(. \/)[^.] (. \.ha)/', $input_line, $output_array);

it results me live this

/myhome/ishere/where/.you.ha

But I need a answer like this

/myhome/ishere/where/you.ha

Please anyone help me to remove this dot.

CodePudding user response：

You can use

/^(. \/)[^.]*\.(.*\.ha)$/

See the regex demo. Details:

• ^ - start of a string
• (. \/) - Group 1: any one or more chars other than line break chars as many as possible and then /
• [^.]* - zero or more chars other than a .
• \. - a . char
• (.*\.ha) - Group 2: any zero or more chars other than line break chars as many as possible and then .ha
• $ - end of a string

CodePudding user response：

You could write the pattern as this, which will give you 2 capture groups that you can use:

(. \/)[^.] \.([^.] \.ha)$

Explanation

• (. \/) Capture group 1, match 1 chars and then the last /
• [^.] Match 1 non dots
• \. Match a dot
• ([^.] \.ha) Match non dots, then .ha
• $ End of string

Regex demo | Php demo

If you use $1$2 in the replacement:

$pattern = "/(. \/)[^.] \.([^.] \.ha)$/";
$s = "/myhome/ishere/where/are.you.ha";
echo preg_replace($pattern, "$1$2", $s);

Output

/myhome/ishere/where/you.ha

Or see a code an example using preg_match with 2 capture groups.

CodePudding user response：

Although I got the answer I was mistaking to put \. in between

(. /)[^.] \.(. \.ha)

preg_replace('/(. \/)[^.] \.(. \.ha)/', '$1$2', $input_lines);

This is how it works.