if image[i][j][1]>=lower_red and image[i][j][1]<=upper_red:

ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()

CodePudding user response：

This is the right annswer:

if ((image[i][j][1]>=lower_red).all()) and ((image[i][j][1]<=upper_red).any()):

CodePudding user response：

This does work when called in the correct way...

• I make a suitable image array (list of lists) that has 3 dimensions.
• I set values for upper an lower for testing.
• I then add the logical check with an if-else.

This works:

# example image 3d array
image = [
    [[5,6,5],[1,2,3]],
    [[1,2,3],[5,6,5]]
    ]

# some values to check
lower_red = 10
upper_red = 10

# example of checking
i, j = 0,1
if image[i][j][1]>=lower_red and image[i][j][1]<=upper_red:
    print('done')
else:
    print(image[i][j][1])

result:

2