how to find nearest power in python-CodePudding

You are given two no A And B when A is raised to some power P we get a no X no I want to find the value of X that is closest to B for example if input is 2 and 4 the output should be 4 the thing I tried

def nearestPower(A, B):
    x=math.floor(math.log(B,A))

    x=x 1
    
    number1=A**x
    
    number2=A**x
    
    if(abs(number1-B)>abs(number2-B)):
    
        return number2
    
    else:
    
        return number1

actually I have no idea how to solve it so I am asking it I just started leaning python

CodePudding user response：

You've got the right idea with math.floor(math.log(B,A)). But why are you making number1 and number2 the same? The point of x=x 1 is to make number2 the next power of A after number1, e.g.

def nearestPower(A, B):
    x=math.floor(math.log(B,A))

    number1=A**x
    x=x 1
    number2=A**x
    
    if(abs(number1-B)>abs(number2-B)):
    
        return number2
    
    else:
    
        return number1