Ordering the values of a dictionary with a for loop iteration-CodePudding

I'm a Python Newb and trying to create a dictionary with ordered values.

Since dict.fromkeys only allows me to copy the same value for each key, I've set all values to 0 and tried something like this:

def Ord_Values_in_Dic(D):
    c = 0
    for value in D.values(): 
        c  = 1
        value  = c
        return D

My output only changes the first value of the dictionary to 1 though, instead I'd want the second value to also change to 2, the third value to change to 3 and so on... I don't get if the loop isn't iterating correctly through the dictionary or there's something else wrong.

CodePudding user response：

Since dict.fromkeys only allows me to copy the same value for each key

then it is not right tool for you task. You might use zip to prepare dict from 2 iterables - one for keys, one for values, consider following simple example

keys = ["x","y","z"]
d = dict(zip(keys,range(3)))
print(d)  # {'x': 0, 'y': 1, 'z': 2}

range with single arguments gives subsequent numbers from 0 (inclusive) to given value (exclusive), so in above example: 0,1,2

CodePudding user response：

Got it!

import numpy as np

a = np.linspace(0,100,100)
b = np.sin(a)
c = np.cos(a)
idx = list(range(1,101))

X = dict(zip(b, idx))
Y = dict(zip(c, idx))

This solved it! Thank you :)