I've created a regex to match particular positions of characters in a string. I've tested it, and it seems to be functioning OK. But I'm just curious if there's a better way to make this regex better. I appreciate it.

I need a word that have in position:

1: any letter 2: any number 3: any letter 4: have space 5: any number 6: any letter 7: any number

I have written a Regex like this:

/[a-zA-Z][0-9][a-zA-Z][\s][0-9][a-zA-Z][0-9]/;

CodePudding user response：

You can use this one:

/[a-z]\d[a-z]\s\d[a-z]\d/i

• the 'i' flag make the regexp case-insensitive
• \d is equivalent to [0-9]
• and you don't have to put '\s' between square brackets

CodePudding user response：

Your regex looks good, except that you likely want to:

1. anchor the regex at the beginning and end (if you have no adjacent text around it),
2. or use word boundary/expected adjacent chars (if your pattern is within a bigger string)

Also, \s includes tab and newline, so you might want to use a simple space instead.

Case 1:

/^[a-z][0-9][a-z] [0-9][a-z][0-9]$/i;

Case 2:

/\b[a-z][0-9][a-z] [0-9][a-z][0-9]\b/i;