I have two commas separate variables like below. on a certain condition, I need to merge two variables into a single. Bit confused and unsure if is it possible in bash
Input
SBI=abc,def,ijk
MEM=one,two,three
Expected output
OUT=abc_one,def_two,ijk_three
CodePudding user response:
This is a simple extension of Iterate over two arrays simultaneously in bash, combined with How to split a string into an array in bash.
IFS=, read -ra sbi_arr <<<"$SBI" # convert SBI string to an array
IFS=, read -ra mem_arr <<<"$MEM" # convert MEM string to an array
out= # initialize output variable
for idx in "${!sbi_arr[@]}"; do # iterate by indices
out ="${sbi_arr[$idx]}_${mem_arr[$idx]}," # append to output
done
out=${out%,} # strip trailing comma from output
echo "Output is: $out"
CodePudding user response:
Using bash
here-strings, process substitution and, paste
and tr
utilities:
OUT=$(paste -d_ <(tr , '\n' <<<"$SBI") <(tr , '\n' <<<"$MEM") | tr '\n' ,)
OUT=${OUT%,}
echo "OUT=$OUT"
CodePudding user response:
With sh
.
#!/bin/sh
SBI=abc,def,ijk
MEM=one,two,three
out=$(
while [ -n "$SBI" ] && [ -n "$MEM" ]; do
sbi_first="${SBI%%,*}"
sbi_rest="${SBI#*"$sbi_first"}"
mem_first="${MEM%%,*}"
mem_rest="${MEM#*"$mem_first"}"
SBI="${sbi_rest#,}"
MEM="${mem_rest#,}"
printf '%s_%s,' "$sbi_first" "$mem_first"
done
)
echo "${out%,}"
With bash
#!/usr/bin/env bash
SBI=abc,def,ijk
MEM=one,two,three
while IFS= read -ru3 str0; do
IFS= read -r str1
out ="${str0}_$str1,"
done 3<<< "${SBI//,/$'\n'}" <<<"${MEM//,/$'\n'}"
echo "${out%,}"