How do I type a while loop inside a for loop?-CodePudding

I'm trying to type a for loop so that when the user types a negative integer, it requires to user to type in a positive integer to move on. Note: The program required to have a for loop.

current = []
test = 1

print("Enter 6 integers greater than 0")
for i in range(6):
    userInput = int(input())
    if int(userInput) <= 0:
        test = 0
        while(test != 1):
            print('Integer must be greater than 0')
            userInput = int(input("Enter integer greater than 0\n"))
        if(userInput > 0):
            test = 1
            break
    else:
        current.append(userInput)

CodePudding user response：

You can do something like:

current = []

print("Enter 6 integers greater than 0")
while len(current) < 6:
    userInput = int(input())
    while userInput < 0:
        print('Integer must be greater than 0')
        userInput = int(input("Enter integer greater than 0\n"))
    current.append(userInput)
        
print(current)

I'm not sure what is the purpose of the test so didn't use in the code.

CodePudding user response：

There is no issue with how the while loop is nested within the for loop, however you need to do the if userInput > 0 test inside the while loop.

With your current code, the while loop will run forever as test is never going to change from the value 0 inside the while loop

Here is some code for your consideration

current = []
test = 1

print("Enter 6 integers greater than 0")
for i in range(6):
    userInput = int(input())
    if int(userInput) <= 0:
        while(True):
            print('Integer must be greater than 0')
            userInput = int(input("Enter integer greater than 0\n"))
            if userInput > 0:
                break
    else:
        current.append(userInput)