How to elegantly handle multiple .find() checks in an if check elegantly?-CodePudding

So right now I have a line in my code with multiple value checks that gets extremely bulky. How would I declutter it?

if string.find(a) != -1 and string.find(b) != -1 string.find(b) != -1 and string.find(c)==-1 and string.find(d)==-1 string not in list:

I tried to handle everything in a for loop, which turned out to be quite the hassle to fulfill many conditions, which had me return to the long row above.

CodePudding user response：

An example using map and all

a = "abc 123 321"
i = ["abc", "123", "321"]

if all(map(lambda f: f in a, i)):
    print("All elements of i are in a")

CodePudding user response：

Just nest your ifs for better readability. Time complexity will not be a problem since you are just checking condition:

if string.find(a) != -1 and string.find(b) != -1:
    if string.find(b) != -1 and string.find(c)==-1 and string.find(d)==-1:
        if string not in lst:
            #your code here