I've done a program which counts income per family member and gives a result of funding. There is a problem when one of the family member's "earns negative value" (has a loss), I want it to count negative values as 0.
Example of right answer:
Family members: 4
Children in family: 2
Input family member income (yearly): 414575
Input family member income (yearly): -12500
Input family member income (yearly): 0
Input family member income (yearly): 0
(Monthly) income per person: 8636.98
Amount of funding: 3200
My result is
a = int(input('Family members : '))
b = int(input('Children in family '))
income = c = ('Input family member income YEARLY : ')
stop = "Wrong Data."
if a < b and a <= 0 or b < 0:
print(stop)
elif a == b:
print(stop)
else:
lst = []
for n in range(a):
incomes = float(input(c))
lst.append(incomes)
g = round(sum(lst) / (12 * a), 2)
z = print("MONTLY income per person: ", g)
if g < 1500:
print("Amount of funding: ", (800 * b) (1200 * (a - b)))
elif g >= 1500:
print("Amount of funding: ", (500 * b) (1100 * (a - b)))
elif g > 2500:
print("Amount of funding: ", (300 * b) (900 * (a - b)))
I've tried IF function
if g < 0:
g = 0
but it only counts it as 0 when whole family income is negative (when sum is < 0), and I need it to count every inputed negative income as 0.
CodePudding user response:
The best approach is to use a conditional comprehension, as suggested @Swifty, in the comments.
Here is your code fixed and using more descriptive variable names:
members = int(input('Family members: '))
children = int(input('Children in family: '))
adults = members - children
if members < children and members <= 0 or children < 0:
print('Wrong data.')
elif members == children:
print('Wrong data.')
else:
incomes = []
for _ in range(members):
incomes.append(float(input('Input family member income YEARLY: ')))
monthly_income = round(
sum(income for income in incomes if income > 0) / (12 * members), 2
)
print('MONTHLY income per person: ', monthly_income)
if monthly_income < 1500:
print('Amount of funding:', (800 * children) (1200 * adults))
elif monthly_income >= 1500:
print('Amount of funding:', (500 * children) (1100 * adults))
elif monthly_income > 2500:
print('Amount of funding:', (300 * children) (900 * adults))
Using the input values from your question, the code above will result in the following output:
Family members: 4
Children in family: 2
Input family member income YEARLY: 414575
Input family member income YEARLY: -12500
Input family member income YEARLY: 0
Input family member income YEARLY: 0
MONTHLY income per person: 8636.98
Amount of funding: 3200
You can also use an easier logic (at least in IMHO):
members = int(input('Family members: '))
children = int(input('Children in family: '))
adults = members - children
if members > children and adults > 0 and children >= 0:
incomes = []
for _ in range(members):
incomes.append(float(input('Input family member income YEARLY: ')))
monthly_income = round(
sum(income for income in incomes if income > 0) / (12 * members), 2
)
print('MONTHLY income per person: ', monthly_income)
if monthly_income < 1500:
print('Amount of funding:', (800 * children) (1200 * adults))
elif monthly_income >= 1500:
print('Amount of funding:', (500 * children) (1100 * adults))
elif monthly_income > 2500:
print('Amount of funding:', (300 * children) (900 * adults))
else:
print('Wrong data.')
CodePudding user response:
If I understood the problem, just append the income only if it is >0. So:
for n in range(a):
incomes = float(input(c))
if incomes > 0:
lst.append(incomes)
CodePudding user response:
Have you tried doing it with the variable incomes? If you say:
if incomes < 0:
incomes = 0
So then as soon as the input gets added to the list, it gets counted as zero if its value is negative?