ELSE not executing in the program-CodePudding

fruits = ["mango", "banana", "apple", "yolk", "mulberry"]
letter = input("Enter the letter you want to search: ")
letter2 = input("Enter the second letter you want to search: ")
for word in fruits:
   if word[0].startswith(letter) and word[1].startswith(letter2):
      result = word
      if result == word:
         print(result)
      else:
         print("no result")

i get the result part working but the "no result" output is not showing whenever i enter in the wrong input

CodePudding user response：

the "no result" is not appearing because that never happens.

in the second if statement ( if word[0]......) you have set

result = word

so when the third if statement sees that result is equal to word, it prints the value stored in 'result'

CodePudding user response：

You can use your code like this too

fruits = ["mango", "banana", "apple", "yolk", "mulberry"]
letter = input("Enter the letter you want to search: ")
letter2 = input("Enter the second letter you want to search: ")
flag = False
result=""
for word in fruits:
   if word[0].startswith(letter) and word[1].startswith(letter2):
      flag = True
      result = word



if(flag == False):
   print("no result")
else:
   print(result)

CodePudding user response：

You don't need to use nested if and else conditions. Remember that this code will compare every item from the list and display each result whether they are a match or not.

fruits = ["mango", "banana", "apple", "yolk", "mulberry"]
letter = input("Enter the letter you want to search: ")
letter2 = input("Enter the second letter you want to search: ")
for word in fruits:
   if word[0].startswith(letter) and word[1].startswith(letter2):
         print(word)
   else:
      print("no result")

CodePudding user response：

Instead of assigning 2 variables from 2 inputs, you can concat 2 inputs and assign it to 1 var. From there, you only need to check if word start with letters when iterating the fruits list.

Using walrus operator (:=), you can assign a variable while printing and reuse it to print whether its value is None or False

fruits = ["mango", "banana", "apple", "yolk", "mulberry"]
letters = input("Enter the letter you want to search: ")   input("Enter the second letter you want to search: ")
for word in fruits:
    if word.startswith(letters): 
        print(result := word)
if not result: 
    print('Not Found')

# Enter the letter you want to search: m
# Enter the second letter you want to search: u
# mulberry

Or one liner:

fruits = ["mango", "banana", "apple", "yolk", "mulberry"]
letters = input("Enter the letter you want to search: ")   input("Enter the second letter you want to search: ")

print(res[0] if (res := [w for w in fruits if w.startswith(letters)]) else 'Not Found')

# Enter the letter you want to search: m
# Enter the second letter you want to search: b
# Not Found

CodePudding user response：

Why are you comparing with 'startwith'? you can compare it directly like this:

if word[0] == letter1 and word[1] == letter2:

Do something like this:

fruits = ["mango", "banana", "apple", "yolk", "mulberry"]
letter = input("Enter the letter you want to search: ")
letter2 = input("Enter the second letter you want to search: ")
result = ""

for word in fruits:
   if word[0] == letter and word[1] == letter2:
      result = word
      break
  
if len(result) > 0:
         print(result)
else:
         print("no result")