Why my code is giving the error name 'sin' is not defined?-CodePudding

I'm trying to implement a code for the following function: f(x) = sen(2πx), x ∈ [0, 2], to get the graph of it. But I'm getting the return that the sine is not defined. I'm not quite understanding what I would have to correct. I would be grateful if someone can help me

Code I used:

import math
import numpy as np
import matplotlib.pyplot as plt

def f(x): return sin*(2*np.pi*x)  
  
x = np.linspace(0,2)  
plt.plot(x, f(x))    
plt.grid()  
plt.show()

This was the only code I thought of to solve this issue, because I thought it would print correctly and without errors

CodePudding user response：

Because the sine function is defined inside numpy, so you should explicitly specify the library where the function is defined:

def f(x): return np.sin*(2*np.pi*x)

CodePudding user response：

The problem is that you are trying to use the sin function without import it. You can find the function in the numpy package:

import numpy as np
import matplotlib.pyplot as plt

def f(x):
    return np.sin(2*np.pi*x)  

x = np.linspace(0,2)  
plt.plot(x, f(x))    
plt.grid()  
plt.show()