Return a string that has been repeated a specified number of times, with a given separator-CodePudding

I am having trouble trying to get my string to repeat the amount of times I want it to.

Here is my code, but I am not sure where I am going wrong.

def respond_echo(input_string, number_of_echoes, spacer):
    
    echo_output = ''
    if len(input_string) > 0:
         for i in range(number_of_echoes):
            echo_output  = (input_string spacer) * number_of_echoes
            
    else:
        echo_output = None
            
    return echo_output

respond_echo('meow', 3, '~')

'meow~~~meow~~~meow~~~'

It comes out like this but I want it to look like this

'meow~meow~meow~'

CodePudding user response：

I have corrected it. When I tried the code it output meow~meow~meow~meow~meow~meow~meow~meow~meow~. The problem is that every time in the for loop you are multiplying the string, so I removed it. The corrected code is:

def respond_echo(input_string, number_of_echoes, spacer):

    echo_output = ""
    if len(input_string) > 0:
        for i in range(number_of_echoes):
            echo_output  = input_string   spacer

    else:
        echo_output = None

    return echo_output

CodePudding user response：

Your code above produces 'meow~meow~meow~meow~meow~meow~meow~meow~meow~' because it is redundant to both use a for loop and multiply the string within each for loop using *. You could do one or the other, but * is nice and concise.

You almost had it though. Here is a working runnable example!

#!/usr/bin/env python

def respond_echo(input_string, number_of_echoes, spacer):
    if input_string:
        echo_output = (input_string spacer) * number_of_echoes
        return echo_output
respond_echo('meow', 3, '~')

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