How to split a nested list into multiple nested lists?-CodePudding

I have a nested list shaped like mylist = [[a, b, c, d], [e, f, g, h], [i, j, k, l]] And i need to split the nested lists so that every two items are grouped together like this: Nested_list = [[[a, b], [c, d], [[e, f], [g, h]], [[i, j], [k, l]]

I tried splitting them by them by usinga for loop that appended them but this doesn't work.

CodePudding user response：

mylist = [['a', 'b', 'c', 'd'], ['e', 'f', 'g', 'h'], ['i', 'j', 'k', 'l']]

nested_list = [ [i[:2], i[2:]] for i in mylist ] 

print(nested_list)

Output:

[[['a', 'b'], ['c', 'd']], [['e', 'f'], ['g', 'h']], [['i', 'j'], ['k', 'l']]]

CodePudding user response：

mylist = [['a', 'b', 'c', 'd'], ['e', 'f', 'g', 'h'], ['i', 'j', 'k', 'l']]
Nested_list = []
for x in mylist:
    Nested_list.append(x[:2])
    Nested_list.append(x[2:])
print(Nested_list)

Output: [['a', 'b'], ['c', 'd'], ['e', 'f'], ['g', 'h'], ['i', 'j'], ['k', 'l']]

CodePudding user response：

import numpy as np

Nested_list = np.array(mylist).reshape(-1,2,2)

output:

array([[['a', 'b'],
        ['c', 'd']],

       [['e', 'f'],
        ['g', 'h']],

       [['i', 'j'],
        ['k', 'l']]], dtype='<U1')

CodePudding user response：

from itertools import * 

my_list = chain.from_iterable(my_list)
def grouper(inputs, n):
    iters = [iter(inputs)] * n
    return zip_longest(*iters)

print(list(grouper(my_list, 2)))