select values from a list after a matching condition-CodePudding

I've a list of data and want to get values after a matching keyword from another list and append it to a dictionary. it should run until the next keyword is matched and added to a new dictionary.

a = ['Experience',
 'Software Engineer',
 'EY',
 'Sep 2018 - Present',
 'Education',
 'xyz College',
 'Bachelor of Technology - BTech, Computer Science',
 '2014 - 2017',
 'Licenses',
 'The Joy of Computing using Python ',
 'NPTEL',
 'Issued Jan 2020']

b = ['Experience', 'Education', 'Licenses']

Expected result:

c = 
    {'Experience':['Software Engineer','EY', 'Sep 2018 - Present']}, 
    {'Education':['xyz College','Bachelor of Technology - BTech, Computer Science','2014 - 2017']}, 
     {'Licenses':
     ['The Joy of Computing using Python ','NPTEL','Issued Jan 2020']}

for i in a:

    j = a.index(i)
    k = 1
    while i in b:
        c[i].append(a[j 1])
        if i == a[k]:
            k =1
            break
        else:
            j =1

but the logic is not correct and I'm stuck here.

CodePudding user response：

I would do a dict-comprehension and append the last element separately:

c = {keyword:a[a.index(keyword)   1:a.index(next_keyword )] for keyword, next_keyword in zip(b, b[1:])}
c[b[-1]] = a[a.index(b[-1]):]

print(c)
# {'Experience': ['Software Engineer', 'EY', 'Sep 2018 - Present']}
# {'Education': ['xyz College', 'Bachelor of Technology - BTech, Computer Science', '2014 - 2017']}
# {'Licenses': ['Licenses', 'The Joy of Computing using Python ', 'NPTEL', 'Issued Jan 2020']}

CodePudding user response：

You can loop through a, change the variable curr_key to the key if it is found in list b and append the elements to that.

c = {}
curr_key = None
for string in a:
    if string in b:
        curr_key = string
    else:
        c.setdefault(curr_key, []).append(string)

print(c)

Output:

{'Experience': ['Software Engineer', 'EY', 'Sep 2018 - Present'],
 'Education': ['xyz College',
  'Bachelor of Technology - BTech, Computer Science',
  '2014 - 2017'],
 'Licenses': ['The Joy of Computing using Python ',
  'NPTEL',
  'Issued Jan 2020']}

CodePudding user response：

I modified the variable names for better understanding:

for keyword in b:
    c[keyword] = []
    for i in range(len(a)):
        if a[i] == keyword:
            c[keyword].append(a[i 1])
            c[keyword].append(a[i 2])
            c[keyword].append(a[i 3])

CodePudding user response：

One way using a loop (assuming you have unique keys):

B = set(b)
c = {}
key = None
for s in a:
    if s in B:
        key = s
        c[key] = []
    elif key is not None:
        c[key].append(s)
print(c)

Output:

{'Experience': ['Software Engineer', 'EY', 'Sep 2018 - Present'],
 'Education': ['xyz College',
  'Bachelor of Technology - BTech, Computer Science',
  '2014 - 2017'],
 'Licenses': ['The Joy of Computing using Python ',
  'NPTEL',
  'Issued Jan 2020']}

If you really want a list of individual dictionaries:

B = set(b)
c = []
key = None
for s in a:
    if s in B:
        key = s
        d = {key: []}
        c.append(d)
    elif key is not None:
        d[key].append(s)
print(c)

Output:

[{'Experience': ['Software Engineer', 'EY', 'Sep 2018 - Present']},
 {'Education': ['xyz College', 'Bachelor of Technology - BTech, Computer Science', '2014 - 2017']},
 {'Licenses': ['The Joy of Computing using Python ', 'NPTEL', 'Issued Jan 2020']}]