How do check for a palindrome in Python?-CodePudding

I am given word and I have to check if the word is a palindrome. My program works well until I play around with the case of the word.

def isPalindrome(word):
    reversedWord = word[::-1]
    palindrome = true
    for n in range(len(word)):
        if(word[n] != reversedWord[i])
            palindrome = false
    return palindrome

I tried the below code and it works well if I feed the function the word "mom", however it fails when I give it the same word but with a different case "Mom"

def isPalindrome(word):
    reversedWord = word[::-1]
    palindrome = true
    for n in range(len(word)):
        if(word[n] != reversedWord[i])
            palindrome = false
    return palindrome

CodePudding user response：

You are already reversing the string. Just return reversedWord.lower() == word.lower() instead of checking character by character.

CodePudding user response：

You need to normalise the string to either upper- or lower-case.

def isPalindrome(word):
  word = word.lower()
  return word == word[::-1]

CodePudding user response：

You would have to compare the lowercase version of the word to its reversed version. There is a function in Python that transforms a String to all-lowercase. Search for it and try it out :)

CodePudding user response：

The hex values of m and M in ascii table are different from each other. Since these values are different in logic comparison, the result will be not a polydrome.

CodePudding user response：

You could transform your word into lowercase (or uppercase) and then check if the reversed if it is a palindrome.

def isPalindrome(word):
    word = word.lower()
    return True if word == word[::-1] else False

isPalindrom("Mom") returns True

CodePudding user response：

The simplest form to this is where you use Ternary operator and Python String lower() method as given below:

def isPalindrome(word):
    return True if (word.lower() == word[::-1].lower()) else False