The program should display ‘Out of range’ if credits entered are not in the range 0, 20, 40, 60, 80,-CodePudding

To try to solve the question above I tried by creating a list with the range and then a list with the variables in it. Then to check if the variables are in the list i used an if loop however it is not working and only printing out "out of range...". I have also tried a while loop and it would just repeat the total 7 times. I do not know how to fix it and would please like an answer. Thank you

def main():
    a = [0, 20, 40, 60, 80, 100, 120]
    try:
        userPass = int(input("Enter pass credits: "))
        userDefer = int(input("Enter defer credits: "))
        userFail = int(input("Enter fail credits: "))
    except:
        print("Invalid number.")
    total = userFail   userPass   userDefer
    aValues = [ userPass, userFail, userDefer ]
    if aValues in a:
        print(total)
    else:
        print("Out of range. Try again")
    if total > 120:
        print("Total incorrect")
        repeat()
    else:
        if userPass >= 120:
            print("This student has progressed.")
            repeat()
        elif userPass >= 100 and total == 120:
            print("This student is trailing.")
            repeat()
        elif userFail <= 60 and total == 120:
            print("This student did not progress(module retreiver).")
            repeat()
        elif userPass <= userFail:
            print("This students program outcome is exclude.")
            repeat()
        else:
            print("incorrect. Try again.")
            repeat()
            
def repeat():
    choice = int(input("If you would like to quit type 1 or test another student write 2: "))
    if choice != 1 and choice != 2:
        repeat()
    else:
        while choice == 2:
            main()
        while choice == 1:
            break
        print("Thank you.")

main()

CodePudding user response：

Testing whether one set of numbers is in another is a set operation. So use set and subtract all of the valid values from your input. If any values remain, they are not valid.

a = set([0, 20, 40, 60, 80, 100, 120])
if set([userPass, userFail, userDefer]) - a:
    print("Out of range. Try again")

Interestingly, you can also use a range object. It is built to check for containment efficiently

a = range(0, 121, 20)
if any(val in a, for val not in (userPass, userFail, userDefer)):
    print("Out of range. Try again")

CodePudding user response：

You need to change the first if.

if aValues[0] in a and aValues[1] in a and aValues[2] in a :
    print(total)

if you need to put more values you can do this:

total=0
for i in range(len(aValues)):
  if(aValues[i] in a):
    total=total  aValues[i]
  else:
    print('Incorrect Value')
print(total)