i tried this but my answer came 0.00 in every input-CodePudding

The series:- I want to write a python program in which we can can input the the value of x and n and solve this series. can anyone help me please? The Series:- x-x^2 x^3/3-x^4/4 ...x^n/n

x = int (input ("Enter value of x: "))
numbed = int (input ("Enter value of n: "))
summed = 0

for a in range (numbed   1) :
    if a%2==0:
        summed  = (x**a)/numbed
    else:
        summed -= (x**a)/numbed
print ("Sum of series", summed)

**I tried this code, but no matter what values I enter, the output is always 0.00. **

CodePudding user response：

This should do the trick:

x = int(input("Enter value of x: "))
n = int(input("Enter value of n: "))
total = x

for i in range(2, n 1):
    if i%2==0:
        total -= x**i/i
    else:
        total  = x**i/i
        
print("Sum: ", total)

CodePudding user response：

I assume the series you mentioned in your question is this: x - x^2/2 x^3/3 - x^4/4 ... x^n/n.

If yes, try this:

x = int (input ("Enter value of x: "))
    numbed = int (input ("Enter value of n: "))
    sum1 = x
    
    for i in range(2,numbed 1):
        if i%2==0:
            sum1=sum1-((x**i)/i)
        else:
            sum1=sum1 ((x**i)/i)
    print("The sum of series is",round(sum1,2))

CodePudding user response：

just as an example of using recurcion:

x = int(input("Enter value of x: "))
n = int(input("Enter value of n: "))

def f(x,n,i=1,s=1):
    return 0 if i>n else x**i/i*s   f(x,n,i 1,-s)

f(3,5)  # 35.85

CodePudding user response：

I have just tried this (removed a few spaces) and it gave me 813802.1 for x=5 and n=10. Could you give a few more details about what you are trying so I can try to spot what's going wrong for you?

x = int(input ("Enter value of x: "))
numbed = int(input ("Enter value of n: "))
summed = 0

for a in range (numbed   1):
    if a%2==0:
        summed  = (x**a)/numbed
    else:
        summed -= (x**a)/numbed
print ("Sum of series", summed)