How to exclude every number that has 1 and print the rest that the user has inputted and match the i-CodePudding

I'm having trouble coding this program in JAVA

Ask the user an integer number then print 1 to n where is input number. if the number have a 1 skip that number and make sure match the length of n number to the output.

Example:

input: 22

output 2 3 4 5 6 7 8 9 20 22 23 24 25 26 27 28 29 30 32 33 34 35 - Total of 22 numbers

skipped all numbers with 1 and matched the length of the inputted numbers

I tried doing conditional statements, nested ifs and for loop but i failed and i badly need some lessons so i can understand the logic

CodePudding user response：

you can do something like this:

import java.util.Scanner;

public class test {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter a number: ");
        int num = sc.nextInt();
        int count = 0;
        for (int i = 1; count < num; i  ) {
            if (String.valueOf(i).contains("1")) {
                continue;
            }
            System.out.println(i);
            count  ;
        }
        sc.close();
    }
}

Update:

If you do not want to use String.valueOf() you can go like this:

import java.util.Scanner;

public class test {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter a number: ");
        int num = sc.nextInt();
        int count = 0;
        for (int i = 1; count < num; i  ) {
            int val = i;
            boolean hasOne = false;
            while (val > 0) {
                if (val % 10 == 1) {
                    hasOne = true;
                    break;
                }
                val = val / 10;
            }
            if (hasOne) {
                continue;
            }
            System.out.println(i);
            count  ;
        }
        sc.close();
    }
}