How do I find the other elements in a list given one of them?-CodePudding

Given one element in a list, what is the most efficient way that I can find the other elements?

(e.g. if a list is l=["A","B","C","D"] and you're given "B", it outputs "A", "C" and "D")?

CodePudding user response：

Your question-: How do I find the other elements in a list given one of them?

Think like.. How can i remove that element in a list to get all other elements in a list [Quite simple to approach now!!]

Some methods are:-

def method1(test_list, item):
    #List Comprehension
    res = [i for i in test_list if i != item]
    return res

def method2(test_list,item):
    #Filter Function
    res = list(filter((item).__ne__, test_list))
    return res

def method3(test_list,item):
    #Remove Function
    c=test_list.count(item)
    for i in range(c):
        test_list.remove(item)
    return test_list
    
print(method1(["A","B","C","D"],"B"))
print(method2(["A","B","C","D"],"B"))
print(method3(["A","B","C","D"],"B"))

Output:-

['A', 'C', 'D']
['A', 'C', 'D']
['A', 'C', 'D']

CodePudding user response：

There are few ways to achieve this, you want to find the other elements excluding the value. eg l1=[1,2,3,4,5] 2 to excluded l1=[1,3,4,5]

# a list
l1 =["a","b","C","d"]
#input of the value to exclude 
jo = input()
l2=[]
for i in range(len(l1)):
        if l1[i]!=jo:
            l2.append(l1[i])
print(l2)