For example, if i had a 17 digit integer variable. How can i take each digit and store it in a different node separately? That way i have a LinkedList that has 17 as it's length.

I thought there was a function similar to charAt but i could not find one.

CodePudding user response：

What I would do is the following:

1. Convert int to `String
2. Convert each char of this String back to an int and add it to your list

A method to do this can look like this:

private static LinkedList<Integer> getDigitsAsLinkedList(int value) {
    LinkedList<Integer> result = new LinkedList<>();
    
    String valueString = Integer.toString(value);
    
    for(char digitAtPosition : valueString.toCharArray()) {
        result.add(Character.getNumericValue(digitAtPosition));
    }
    
    return result;
}

Be aware that Integer.MAX_VALUE is only 2147483647 whis is only 10 digits. If you want higher numbers, you need to use other types.

Example for usage of the method above:

public static void main(String[] args) {
    System.out.println(getDigitsAsLinkedList(1234567890));
}

This results in an output of [1, 2, 3, 4, 5, 6, 7, 8, 9, 0].

CodePudding user response：

Assuming it's 17 digits, you'd be using long instead of int. Now, you've not mentioned whether the list must be integer or character, for each digit. So, for int output:

LinkedList<Integer> numToIntList(Long num) {
    LinkedList<Integer> result = new LinkedList<>();
    while (num > 0) {
        result.push((int) (num % 10));  // push because we're getting digits in reverse, so this would ensure proper order
        num = num / 10;
    }
    return result;
}

Similarly, a bit extra effort for char:

LinkedList<Character> numToCharList(Long num) {
    LinkedList<Character> result = new LinkedList<>();
    while (num > 0) {
        result.push(Character.forDigit((int) (num % 10), 10));
        num = num / 10;
    }
    return result;
}

Note: in case you have numbers within int range you won't need explicit casting for num % 10 since it's already an integer.