jQuery Ajax sending data to php with one button click but two different actions-CodePudding

What I'm trying to achieve is a user to follow another user without having to refresh the page. So far I've played around and had no problem inserting and deleting the rows in mysql table, but now when I'm trying with AJAX I can't get it to work.

jquery

//the button for following and unfollowing a user
$(document).ready(function(){
$("#followbutton").click(function(e) {
e.preventDefault();
var theuserid = $('#theuserid').val();
var thefollower = $('#thefollower').val();
$.ajax({
url: 'includes/followuser.inc.php',
type: 'post',
data: {'theuserid': theuserid, 'thefollower': thefollower, 'followbutton': true},
success: function(response){

$('#followmessage').html(response);   
$("#followmessage").show().delay(3000).fadeOut();
//I want the button to change its text to Following and when hovering it should say unfollow if user is followed
$('#followbutton').text("Unfollow"); 

}
});
});
});

followuser.inc.php

<?php
require_once 'dbh.inc.php';
require_once 'functions.inc.php';
if (isset($_POST["submitFollow"])){
$userthatisfollowed = $_POST["thefollower"];
$theuserid = $_POST["theuserid"];

mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$stmt = $conn->prepare('INSERT INTO userfollow (thefollower, theuserid, followstatus) VALUES (?,?,?)');
$followstatus = 1;
$stmt->bind_param('sss', $userthatisfollowed, $theuserid, $followstatus);
$stmt->execute();
echo $response = "<span>Followed!</span>";
$stmt->close();

} else if(isset($_POST["submitUnfollow"])){
$userthatisfollowed = $_POST["thefollower"];
$theuserid = $_POST["theuserid"];
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$stmt = $conn->prepare('DELETE userfollow FROM userfollow WHERE thefollower = ? AND theuserid = ?');

$stmt->bind_param('ss', $userthatisfollowed, $theuserid);
$stmt->execute();
echo $response = "<span>Unfollowed!</span>";
$stmt->close();
} else {
    echo "DID NOT WORK";
}

profile.php

if(isset($_SESSION["userid"]) && $_SESSION["userid"] != $userthatisfollowed) {
?>
<form action="<?php echo htmlspecialchars("includes/followuser.inc.php");?>" id="followform" method="post">
<?php

//if record is found in table, show Unfollow button, else Follow
if ($result->num_rows > 0){
$subscribe_status = "Unfollow";
} else {
$subscribe_status = "Follow";
}

//Here the button should change to Unfollow or Follow
echo "<button name='submit".$subscribe_status."' id ='followbutton' type='submit'>";
echo "<span>Follow</span>";
echo "</button>";

//this is just a notification bell for later
echo "<button name='submit".$subscribe_status."' id ='notificationbell' type='submit'>";
echo "<i class='fa fa-bell'></i>";
echo "</button>";

//the feedback message
echo "<div id='followmessage'></div>";

?>
<input type="hidden" name="theuserid" id="theuserid" value="<?php echo $_SESSION["userid"] ?>">
<input type="hidden" name="thefollower" id="thefollower" value="<?php echo $userthatisfollowed; ?>">
</form>
<?php
}

What's worth noting is that I'm getting the response DID NOT WORK which tells me that if(isset($_POST["submitUnfollow"])) is not set. However, If I try with if(isset($_POST["theuserid"]) && (isset($_POST["thefollower"])) then it actually works for the insert query but not for the delete query.

CodePudding user response：

You're missing the submitFollow parameter in the data: object. Instead, you have followbutton: true, which isn't used by the PHP code. So change that to:

data: {'theuserid': theuserid, 'thefollower': thefollower, 'submitFolow': 'true'},

And for the unfollow button, use submitUnfollow instead.