Count unique five letter words in file and ignore words with '-CodePudding

I need to count all unique five letter words in a txt file and ignore any word with an apostrophe. I'm new to python so I am quite confused trying to get just the five letter words and not sure how to ignore words that have an ' . what I wrote so far seemed to work for filtering the unique words but not for just five letter words.

with open ("names.txt", 'r') as f:  #open the file
    words = f.read().lower().split()  #read the contents into a sting, made all the character in string lower case and split string into list of words
    print(words)     


unique_words = set(words) #get unique words
print(len(unique_words)) 

for w in unique_words:
    if len(w) == 5:
       print(unique_words)
    else:
        pass

CodePudding user response：

Your code looks good. I think the only bit you did wrong was to print(unique_words) instead of print(w) when you found a word w of length 5.

To ignore the words containing ' you can add this condition:

for w in unique_words:
    if len(w) == 5 and "'" not in w:
       print(w)

B.t.w. you don't need the pass statement if you are already at the end of the for loop.

CodePudding user response：

This should do the trick

with open("names.txt", 'r') as f:  #open the file
    words = f.read().lower().split()  #read the contents into a sting, made all the character in string lower case and split string into list of words
    print(words)     

unique_words = set() #Create empty set
for w in words:
    if len(w) == 5 and "'" not in w:
       unique_words.add(w) #add words to set

print(len(unique_words))