var group = 4;
var level = [1,2];
var options = 'ng;nk';
var arrayWithCorrectGroup = shuffledArray.filter(innerArray => innerArray[0] === group);
var arrayWithCorrectLevels = arrayWithCorrectGroup.filter(x => x[1] === level[0] || x[1] === level[1] );
var arrayWithCorrectValues = arrayWithCorrectLevels.filter(x => x[3].includes(...options.split(';')));
When using .includes
as seen in arrayWithCorrectValues
, you can use the three dots to loop through all options in the array. I want to know if there is a similar way for the equals or in the arrayWithCorrectLevels
. It's possible to have an array with 10 levels. I don't want to write x[1] === level[n]
ten times.
CodePudding user response:
There are several ways to check if x[1] is equal to any element of the level array.
Example one:
level.includes(x[1]);
Example two:
level.some(item => item === x[1]);