How I can compare the length of song time?-CodePudding

I need to compare the length of song tme to find what song in my play list is the longest and print his name. I got a list with all the times, for example I got the list ['5:13', '4:05', '4:15', '4:23', '4:13'] and now I need to compare the times but I have no idea how to convert the str list to int list and compare the times. Any suggetions?

CodePudding user response：

use the datetime module to convert the strings representing the durations to datetime objects and compare them. since you have not mentioned how you store the song names I consider their indexes to show.

from datetime import datetime

durations = ['5:13', '4:05', '4:15', '4:23', '4:13']
dt_durations = [datetime.strptime(duration, '%M:%S') for duration in durations]
max_duration = max(dt_durations, key=lambda x: (x - datetime.min).total_seconds())
print(f"index {dt_durations.index(max_duration)} is the longest which has a duration of {max_duration.strftime('%M:%S')}")

the output would be:

index 0 is the longest which has a duration of 05:13

CodePudding user response：

max() provides a way to use a key function to convert each item in the list.

def seconds(x):
  m, s = x.split(':')
  return int(m) * 60   int(s)

durations = ['5:13', '4:05', '4:15', '4:23', '4:13']
m = max(durations, key=seconds)
print(m) # will print '5:13'

CodePudding user response：

Short and painless:

durations=['5:13', '4:05', '4:15', '4:23', '4:13', '11:05']
print(sorted(durations, key=lambda x: tuple(map(int, x.split(":")))))

Output

['4:05', '4:13', '4:15', '4:23', '5:13', '11:05']