I am getting this error I am using filter function to filter the odd values from list

Code:

l1=[1,2,4,5,6,79,100,200,500]
finnal_list=list(filter(lambda x: (x%2!=0),l1))
print(finnal_list)

l1=[1,2,4,5,6,79,100,200,500]
finnal_list=list(filter(lambda x: (x%2!=0),l1))
print(finnal_list)

CodePudding user response：

Error clearly says in your previouse cells you've assigned filter varaible. It's a bad practice to use builtin names as vafraible names. Like so example '

#old cells code 
filter = "some string"
#old cells code 


l1=[1,2,4,5,6,79,100,200,500]

finnal_list=list(filter(lambda x: (x%2!=0),l1))
print(finnal_list)

Throws error #

Error: TypeError: 'str' object is not callable

Fix

Simply clear that variable if you dont need it

#old cells code
filter = "some string"
#old cells code

l1=[1,2,4,5,6,79,100,200,500]  
del filter
finnal_list=list(filter(lambda x: (x%2!=0),l1))
print(finnal_list)

output #

[1, 5, 79]

CodePudding user response：

It is simpler to just use a List comprehension

final_list = [x for x in l1 if x%2 != 0]

CodePudding user response：

li = [1,2,4,5,6,79,100,200,500]
print(list(filter(lambda x: x if x%2!=0 else None,l1)))