I have a sentence

s = 'john had a little blue car'

which I want to split into three different strings (of word length 2) to obtain

'john had'
'a little'
'blue car'

How can I do this using split? First I tried splitting via

s.split(" ")

to give

['john', 'had', 'a', 'little', 'blue', 'car']

how can I now take that list of words and join them to obtain the result I want?

CodePudding user response：

Regex

Using a regex:

import re

r = r"(\w \s \w )"
s = "john had a little blue car"
m = re.findall(r, s)

• (\w \s \w )
  _{Regex101 Demo}

  • \w: matches any word character
  • \s: matches any whitespace
  • : as many times possible

• re.findall():

  Return all non-overlapping matches of pattern in string, as a list of strings or tuples.

Try it online!

---

Python

A native Python way is to use the s.split() as you described, and then 'splice' the array and join() them back together in groups of 2 using a for loop with range(0, len(s), 2) to take steps of 2:

s = 'john had a little blue car'
s = s.split(" ")
s = [' '.join(s[i : i   2]) for i in range(0, len(s), 2)]

Try it online!

---

Both result in:

['john had', 'a little', 'blue car']

CodePudding user response：

Not the fastest way to be honest:

s = 'john had a little blue car'.split()

for i in range(0, len(s), 2):
    print(f"{s[i]} {s[i 1]}")

Where: s[i] - first elem of pair, s[i 1] - second elem of a pair

CodePudding user response：

The result you wants is a bit blurry, but here a few ways

1. Using for loop to iterate over the string and combining pairs of words together:

    s = 'john had a little blue car'
    words = s.split()
    for i in range(0, len(words), 2):
        w1 = words[i]
        w2 = words[i 1]
        print(w1, w2)
   

if you want to save the result than :

    s = 'john had a little blue car'
    split_list = []
    words = s.split()
    for i in range(0, len(words), 2):
            w1 = words[i]
            w2 = words[i 1]
            split_list.append([w1, w2])

after the code you will have in split_list in each cell the 2 of the words

2. Using the zip function to iterate over the string and combining pairs of words together (Might not familiar with Zip but its a very helpful tool):

    s = 'john had a little blue car'
    words = s.split()
    for w1, w2 in zip(words[::2], words[1::2]):
        print(w1, w2)
   

if you want to save the result than :

    s = 'john had a little blue car'
    split_list = []
    words = s.split()
    for w1, w2 in zip(words[::2], words[1::2]):
        split_list.append([w1, w2])

after the code you will have in split_list in each cell the 2 of the words

CodePudding user response：

s = 'john had a little blue car'.split(' ')    
#['john', 'had', 'a', 'little', 'blue', 'car']

s[0::2]
#['john', 'a', 'blue']

s[1::2]
#['had', 'little', 'car']


list(zip(s[0::2],s[1::2]))
#[('john', 'had'), ('a', 'little'), ('blue', 'car')]

Or for desired output:

[' '.join(x) for x in zip(s[0::2],s[1::2])]
#['john had', 'a little', 'blue car']