How to split list of coordinates into separate variables?-CodePudding

I'm trying to split coordinates of elements that I find like this

elements = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//span[text() ='100']")))

When I only have to find coordinates of element that appears only once I just use .location, but my problem is when I have to find element that appears more then once. I tried doing it like this but it doesn't work

elements = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//span[text() ='100']")))

elementlist = []

for element in elements:
    elementlocation = element.location
    elementlist.append(location)
    print(elementlist)

x,y = elementlist.split(",")
print(x,y)

I tried getting list of coordinates of element that appears multiple times, split them into separate variables x,y and print them out

CodePudding user response：

You didn't say what are your elements, but considering they are instances of some class which has location property:

element_locations = [x,y for x,y in element.location.split(",") for element in elements]
# This is gonna be a list [(x1,y1), (x2,y2), ...,(xn,yn)]

CodePudding user response：

To print the x,y location of the elements you can use:

print([element.location for element in WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//span[text() ='100']")))])
# outputs -> [{'x': 100, 'y': 367}, {'x': 100, 'y': 684}, {'x': 100, 'y': 684}, {'x': 100, 'y': 684}, {'x': 100, 'y': 1917}]

To print only the coordinates:

print([(element.location['x'],element.location['y']) for element in WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//span[text() ='100']")))])
# outputs -> [(100, 367), (100, 684), (100, 684), (100, 684), (100, 1917)]