Map function required to get an abs value of a given I/P-CodePudding

Below is my sample code:-

def applyToEach(L, f):
  for i in range(len(L)):
    L[i] = f(L[i])

L = [1, -2, 3.333]
print('L = ', L)
print('Apply abs to each element of L.')
applyToEach(L, abs)
print('L = ', L)

Below is the O/p on the same:-

L =  [1, -2, 3.333]
L =  [1, 2, 3.333]

I would like to go for a map function that will modify my existing function applyToEach, so instead of using the one I used before, how can i use map function at applyToEach to get abs value of L?

CodePudding user response：

use map function:

map(abs, <your-list>)

CodePudding user response：

map or a list comprehension will return a new object. You can't mutate existing object using those, but you can use this trick:

def applyToEach(L, f):
    my_list[:] = map(f, my_list)

my_list[:] = [f(i) for i in my_list]

these will modify my_list in place.

CodePudding user response：

You can try this:

def applyToEach(L, f):
    L[:] = map(f, L)

L = [1, -2, 3.333]
print('L = ', L)
print('Apply abs to each element of L.')
applyToEach(L, abs)
print('L = ', L)

Output:

L =  [1, -2, 3.333]
Apply abs to each element of L.
L =  [1, 2, 3.333]