I am running a server with Flask using the following code:
from flask import Flask, flash, request, redirect, url_for
app = Flask(__name__)
@app.route('/', methods=['POST'])
def upload_file():
# check if the post request has the file part
print(request.files.__dict__)
print(request.form.__dict__)
print(request.data)
return ""
app.run(host='0.0.0.0', port=5000);
I run it with the command "python server2.py" where server2.py is the server code above. I am in a virtual environment with Flask installed.
In a separate shell on the same machine, at the command line, I run:
curl -F [email protected] http://192.168.1.25:5000
I expect to see something present and printed out in that first print statement, the one for request.files.__dict__.
Instead, I see this output:
* Serving Flask app 'server2' (lazy loading)
* Environment: production
WARNING: This is a development server. Do not use it in a production deployment.
Use a production WSGI server instead.
* Debug mode: off
* Running on all addresses.
WARNING: This is a development server. Do not use it in a production deployment.
* Running on http://192.168.1.25:5000/ (Press CTRL C to quit)
{}
{}
b''
192.168.1.25 - - [09/Sep/2021 18:58:41] "POST / HTTP/1.1" 200 -
This says to me that curl communicated to my server, and the server accepted the communication (200), but, the server didn't put anything in request.files.__dict__.
Can anyone help me understand why this short Flask program isn't communicating with curl in the way I expect?
Thanks!
CodePudding user response：
Everything works as expected, except the way you try to read the data.
You need to access the data e.g. via request.files["onlyFile"].
request.files is not a standard Python dict, but an ImmutableMultiDict.
How do I know? I set a breakpoint and inspected the state of request.
That is not too hard - I did a 5 min lightning talk how to debug Flask applications: