I have multiple pandas dataframes:
df1
df2
df3
And I want to export them all to csv files.
df1.to_csv('df1.csv', index = False)
df2.to_csv('df2.csv', index = False)
df3.to_csv('df3.csv', index = False)
What's the most efficient way to do this?
def printToCSV(number):
num = str(num)
csvTemp = "df99.csv"
csv = csvTemp.replace('99',num)
dfTemp = "df99"
dfString = dfTemp.replace('99',num)
#i know i cant use the .to_csv function on a string
#but i dont know how iterate through different dataframes
dfString.to_csv(csv, index = False)
for i in range(1,4):
printToCSV(i)
How can I can call different dataframes to export?
CodePudding user response:
You can add them all to a list with:
list_of_dataframes = [df1, df2, df3]
Then you can iterate through the list using enumerate to keep a going count of which dataframe you are writing, using f-strings for the filenames:
for count, dataframe in enumerate(list_of_dataframes):
dataframe.to_csv(f"dataframe_{count}.csv", index=False)
CodePudding user response:
When you are creating the dataframes you can store them in a suitable data structure like list and when you want to create csv you can use map and do the same.
dfs = []
for i in range(10):
dfs.append(DataFrame())
result = [dfs[i].to_csv(f'df{i}') for i in range(10)]
CodePudding user response:
If you want to stick with your function approach, use:
df_dict = {"df1": df1, "df2": df2, "df3": df3}
def printToCSV(num):
df_dict[f"df{num}"].to_csv(f"df{num}.csv", index=False)
printToCSV(1) # will create "df1.csv"
However, if you want to increase efficiency, I'd propose to use a df
list (as @vtasca proposed as well):
df_list = [df1, df2, df3]
for num, df in enumerate(df_list): # this will give you a number (starting from 0) and the df, in each loop
df.to_csv(f"df{num}.csv", index=False)
Or working with a dict
:
df_dict = {"df1": df1, "df2": df2, "df3": df3}
for name, df in df_dict.items():
df.to_csv(f"{name}.csv", index=False)