how to save images in to particular path when image is give from link or url, in python-CodePudding

I'm trying to save images that are given from link, such a way that, image save in the given path and image file_name is created with uuid like below:

my profile model is:

class Profile(DataTimeModel):
    first_name = models.CharField(max_length=100)
    middle_name = models.CharField(max_length=100, null=True, blank=True)
    last_name = models.CharField(max_length=100)
    email_address = models.CharField(max_length=100)
    phone_number = models.CharField(max_length=100)
    address = models.CharField(max_length = 255, null=True, blank=True)
    citizenship_no = models.CharField(max_length = 25, null=True, blank=True)
    created_by = models.ForeignKey(User, on_delete=models.SET_NULL, null=True, blank=True)

Now when the profile is enrolled I will send multiple image link or single, from these link I need to download the image and save to the file path like below:

root_dir = MEDIA_ROOT '/profile/'
new_dir = str(profile.id)
file_name = str(uuid.uuid4()) '.jpeg'
path = os.path.join(root_dir, new_dir)
os.makedirs(path)

Now, I need to save the image that comes from the URL into the path folder with image name file_name with extension. How can I do that? I try by using urllib.request.urlretrieve(url, file_name)

this but it saves into base directory but I need to save in given path.

Image link is given from this interface:

CodePudding user response：

Even if the parameter in urlretrieve is called filename, you may actually pass in a file path:

Simply combine your path and file_name:

path = os.path.join(root_dir, new_dir)
os.makedirs(path)
file_name = str(uuid.uuid4()) '.jpeg'
file_path = os.path.join(path, file_name)
urllib.request.urlretrieve(url, file_path)