How can I separate part of json in python?-CodePudding

I have a json in the following format and I just want to save 2 parts of it. But I get it as separate characters. Can you please help me?

for data in results['results']:
   dictionary = dict(zip("title:", data['title']))
   dictionary = dict(zip("uuid:", data['uuid']))

Json

        results": [
            {
              "title": "subject1",
              "ja_pub_yyyy": 1395,
              "uuid": "86ae6",
              "external_link": null,
              "fulltext_status": 1,
},
  {
              "title": "subject2",
              "ja_pub_yyyy": 1395,
              "uuid": "86ae6",
              "external_link": null,
              "fulltext_status": 1,
}
]

new_result

    results": [
        {
          "title": "subject1",
          "id": "86ae6",
 },
        {
          "title": "subject2",
          "id": "86ae6",
 }]

CodePudding user response：

You are not creating each dict properly. It is more simple:

new_result = []
for data in results['results']:
    l = ((k,data[k]) for k in ("title","uuid"))
    dictionary = dict(l)
    new_result.append(dictionary)

I have demonstrated collecting each dictionary.

CodePudding user response：

you can do it this way too

result = [{'title':r['title'],'uuid':r['uuid']} for r in results]

CodePudding user response：

Try to loop over the json and extract the object property into the new array. eg:

results= [
            {
              "title": "subject1",
              "ja_pub_yyyy": 1395,
              "uuid": "86ae6",
              "external_link": None,
              "fulltext_status": 1,
},
  {
              "title": "subject1",
              "ja_pub_yyyy": 1395,
              "uuid": "86ae6",
              "external_link": None,
              "fulltext_status": 1,
}
]
res = []
for data in results:
    res.append({'name': data['title'], 'id': data['uuid']})
print(res)