I have the below script doing nightly backups of my databases.
If I execute directly via shell, everything works.
However, if via cron as same user execution, I get this error in the log file: nightly-backups.sh: 9: [[: not found
1
2 timestamp=`date %Y-%m-%d`;
3
4 ##### EXECUTE THE MYSQL BACKUP #####
5 echo "Starting MySQL Backup:" `date`;
6
7 databases=`/usr/bin/mysql -e "SHOW DATABASES;" | tr -d "| " | grep -v Database`
8 for db in $databases; do
9 if [[ "$db" != "information_schema" ]] && [[ "$db" != _* ]] && [[ "$db" != "mysql" ]] && [[ "$db" != "performance_schema" ]] ; then
10 echo "Dumping database: $db"
11 /usr/bin/mysqldump --single-transaction --routines --triggers --databases $db > /home/db_backup/backup/mysql/$db-$timestamp.sql
12 /usr/bin/pigz /home/db_backup/backup/mysql/$db-$timestamp.sql
13 fi
14 done
15
16 echo "Finished MySQL Backup:" `date`;
CodePudding user response:
[[: not found
[[ is bash operator. It seems cron executes script with another shell interpreter. You can provide path to interpreter in first line of your script:
#!/bin/bash
or
#!/usr/bin/env bash